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protis

Hello!

Based on this http://net.tutsplus.com/tutorials/php/easy-form-generation-using-fuelphp article I've created a form. In this form there are many checkboxes.I want to group them. For example:

Now the form looks like
checkbox1
checkbox2
checkbox3
checkbox4
checkbox5
checkbox6
checkbox7
checkbox8
checkbox9

What can I do, to make form:

Set of checkboxes1
checkbox1
checkbox2
checkbox3

Set of checkboxes2
checkbox4
checkbox5

Set of checkboxes
checkbox6
checkbox7
checkbox8
checkbox9

If it is need to know, I use ORM

Thank you very much.

Sorry for my English.

Harro

I've quickly glanced at that tutorial.

It does the fieldset generation in the controller (using the build() method), and passing the generated HTML as one single block to the view. To generate custom form layouts, you can not use the build() method anymore.

Instead, pass the fieldset object to the view, and in the view, do something like

<?php echo Form::open(); ?>
<fieldset>
    <legend>Set of checkboxes1</legend>
    <?php echo $fieldset->field('box1')->build(); ?>
    <?php echo $fieldset->field('box2')->build(); ?>
    <?php echo $fieldset->field('box3')->build(); ?>
</fieldset>
<?php echo Form::close(); ?>

protis

Thank you for answer, everything is fine!
I have one more simple question:
$this->template->set('fieldset', $fieldset, false);

Is it only one way to pass the fieldset object to the view? (I'm afraid to use the third parameter "false")

Harro

I'm not sure if it's required to disable encoding on a Fieldset object. Change the false to true and you'll find out. ;-)

protis

Thanks for your answers!

http://fuelphp.com/docs/general/views.html

Here press ctrl+f and enter the next string (it will be on a yellow background):
Note on objects

Here you can see my example.
So, if I change the false to true I recieve
ErrorException [ Error ]: Call to a member function field() on a non-object

That's why I asked this question.

Harro

That would suggest another issue. Encoding doesn't destroy objects.

Are you sure you're passing the fieldset object, and not the result of a build() call to your view?

protis

In controller:

function action_add()
    {
        $fieldset = Fieldset::forge()->add_model('Model_Advert')->repopulate();
...
        $this->template->set('fieldset', $fieldset, false);
    }

and in view

<?php echo Form::open(); ?>
<?php echo $fieldset->field('field_id')->build(); ?>
<?php echo Form::close(); ?>

Are you sure you're passing the fieldset object, and not the result of a build() call to your view?
So, I gues, not... but I'm not sure

Harro

That looks ok, and should work without problems. I do this in every app.

Your model contains a property called 'field_id'?

protis

No, it was just for example.
If I set the third param. false - that is OK - the form is shown as needed, if true -
ErrorException [ Error ]: Call to a member function field() on a non-object
as I wrote above

protis

if 3-d param = true.

<?php echo Form::open(); ?>
<?php echo $fieldset; ?>
<?php echo Form::close(); ?>

This code in view shows in browser code of the form, and in source we can see for example

&lt;td class=&quot;&quot;&gt;&lt;label id=&quot;label_skype&quot; for=&quot;form_skype&quot;&gt;skype&lt;/label&gt;&lt;/td&gt;

Harro

Just checked the code.

Objects can't be encoded unless they have a __toString() magic method, or implement Iterator or ArrayAccess, or are an instance of stdClass.

Since a fieldset object has the magic method, encoding it triggers that method, which causes build() to run on the fieldset, and a string containing HTML to be passed to the View.

So yes, either use false do disable encoding on set(), or whitelist the Fieldset class in the config.

From a security point of view it should not be a problem, the Fieldset should not contain unvalidated data, other then user input which will be re-displayed in a form field.

protis

Thank you very much! I'm very pleasure to learn FuelPHP with you! You are great!

Harro

Thanks for the kudos. That keeps us going!

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