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My question is more about architecture.
I've got an ORM-model Model_Condition for example. And there are another models which extend it: Model_Condition_Category, Model_Condition_Price, etc.

class Model_Condition extends Orm\Model
{
    protected static $_properties = array('id', 'type', 'operator', 'value');
}

Those models store their data in the same table named 'conditions', but have some methods different from Model_Condition :

class Model_Condition_Category extends Model_Category
{
    public function set_form_fields() {}
    public function __toString() {}
    public function execute() {}
}

There is a Model_Project which has one-to-many relations to Model_Condition.

Is it possible to get models by relations as final condition classes?
I came up with a dirty way, but not sure if it is not head-shot:

class Model_Condition extends Orm\Model
{
  public function as_class($type)
  {
    $class = 'Model_Condition_'.ucfirst($type);

    if ( ! class_exists($class))
    {
      throw new \FuelException("Class {$class} not found!");
    }

    return $class::forge( $this->to_array() );
  }
}

$condition = $project->conditions[0];
$condition = $condition->as_class( $condition->type );

I can see an obvious architecture flaw there, but on the other hand it looks like typical issue.
How is it normally done?